#### The properties of a system, during a reversible constant pressure non-flow process at p = 1.6 bar, changed from v_{1} = 0.8 m^{3}/kg, T_{1} = 20°C to v_{2 }= 0.55 m^{3}/kg, T_{2} = 260°C. **c**_{p} = ( 1.5 + ^{75}/_{T + 45 }) ^{kJ}/_{kg °C }, where T is in °C. Determine : (j) Heal added/kg ; (ii) Work done/kg ; (iii) Change in internal energy/kg ; (iv) Change in enthalpy/kg.

**c**

_{p}= ( 1.5 +^{75}/_{T + 45 })^{kJ}/_{kg °C }

The properties of a system, during a reversible constant pressure non-flow process at p = 1.6 bar, changed from v_{1} = 0.8 m^{3}/kg, T_{1} = 20°C to v_{2 }= 0.55 m^{3}/kg, T_{2} = 260°C.

* c_{p} = ( 1.5 + ^{75}/_{T + 45 }) ^{kJ}/_{kg °C }*, where T is in °C.

Determine : (j) Heal added/kg ; (ii) Work done/kg ;

(iii) Change in internal energy/kg ; (iv) Change in enthalpy/kg.

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